The frequency range from $3\, MHz$ to $30\, MHz$ is known as:

The energy of a gamma $(\gamma)$ ray photon is $E_{\gamma}$, and that of an $X$-ray photon is $E_{X}$. If the visible light photon has an energy of $E_{v}$, then we can say that:

The correct match between the entries in column $I$ and column $II$ is:
$I$ (Radiation) | $II$ (Wavelength)
$(a)$ Microwave | $(i)$ $100 \, m$
$(b)$ Gamma rays | $(ii)$ $10^{-15} \, m$
$(c)$ $A.M.$ radio waves | $(iii)$ $10^{-10} \, m$
$(d)$ $X$-rays | $(iv)$ $10^{-3} \, m$

If microwaves,$X$ rays,infrared,gamma rays,ultraviolet,radio waves and visible parts of the electromagnetic spectrum are denoted by $M, X, I, G, U, R$ and $V$ respectively,then which of the following is the arrangement in ascending order of wavelength?

The terminology of different parts of the electromagnetic spectrum is given in the text. Use the formula $E = hv$ (for energy of a quantum of radiation: photon) and obtain the photon energy in units of $eV$ for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation?

What range of the electromagnetic spectrum is considered as visible light?