If the amplitude of the magnetic field component of an electromagnetic wave in vacuum is $B_m = 510 \, nT$,then the amplitude of the electric field component of the wave is ......

All components of the electromagnetic spectrum in vacuum have the same

For an $EM$ wave,the electric field intensity due to a bulb of $100\ W$ at a distance of $3\ m$ is $E$. What is the electric field intensity produced by radiations coming from a $50\ W$ bulb at the same distance?

$A$ radiowave has a maximum electric field intensity of $10^{-4} \, V/m$ on arrival at a receiving antenna. The maximum magnetic flux density of such a wave is:

In fog, photographs of the objects taken with infrared radiations are more clear than those obtained during visible light because

$A$ plane electromagnetic wave has a frequency of $2.0 \times 10^{10} \ Hz$ and its energy density is $1.02 \times 10^{-8} \ J/m^3$ in vacuum. The amplitude of the magnetic field of the wave is close to $....nT$. (Given: $\frac{1}{4 \pi \varepsilon_0} = 9 \times 10^9 \ Nm^2/C^2$ and speed of light $c = 3 \times 10^8 \ m/s$)