In a plane electromagnetic wave,the electric field oscillates sinusoidally at a frequency of $2 \times 10^{10} \, Hz$ and an amplitude of $48 \, V/m$. Find the amplitude of the magnetic field.

  • A
    $16 \times 10^{-8} \, Wb/m^2$
  • B
    $14 \times 10^{-8} \, Wb/m^2$
  • C
    $10 \times 10^{-8} \, Wb/m^2$
  • D
    $12 \times 10^{-8} \, Wb/m^2$

Explore More

Similar Questions

Why is the orientation of the portable radio with respect to the broadcasting station important?

$A$ point source of electromagnetic radiation has an average power output of $800 \ W$. Find the maximum value of the magnetic field at a distance of $3.5 \ m$ from the source.

Difficult
View Solution

$A$ point source of electromagnetic radiation has an average power output of $800\,W$. The maximum value of the electric field at a distance of $3.5\,m$ from the source will be.....$V/m$.

$A$ plane electromagnetic wave is travelling in the positive $X$-axis. At the instant shown,the electric field at the extremely narrow dashed rectangle is in the $-ve$ $Z$-direction and its magnitude is increasing. Which diagram correctly shows the direction and relative magnitudes of the magnetic field at the edges of the rectangle?

If an electromagnetic wave is propagating in the $x$-direction and the magnetic field $\vec{B}$ at any instant is in the $z$-direction,then at that instant,the electric field $\vec{E}$ will be in the ........ direction.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo