Electromagnetic waves with wavelengths rangin | vedclass

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(B) Given: $\lambda_1 = 3 	imes 10^{-3} \, m$,$\lambda_2 = 1 \, m$,and $c = 3 	imes 10^8 \, m/s$.The frequency $f$ is given by $f = \frac{c}{\lambda

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$3 	imes 10^2 \, MHz$ to $10^5 \, MHz$

Vedclass · Answer

(B) Given: $\lambda_1 = 3 	imes 10^{-3} \, m$,$\lambda_2 = 1 \, m$,and $c = 3 	imes 10^8 \, m/s$.The frequency $f$ is given by $f = \frac{c}{\lambda}$.For $\lambda_1 = 3 	imes 10^{-3} \, m$:$f_1 = \frac{3 	imes 10^8}{3 	imes 10^{-3}} = 10^{11} \, Hz = 10^5 \, MHz$.For $\lambda_2 = 1 \, m$:$f_2 = \frac{3 	imes 10^8}{1} = 3 	imes 10^8 \, Hz = 3 	imes 10^2 \, MHz$.Thus,the frequency range is $3 	imes 10^2 \, MHz$ to $10^5 \, MHz$.

Part of the electromagnetic spectrum	Applications
$P$. Microwave	$I$. For purifying the water
$Q$. $UV$ rays	$II$. For warming the food
$R$. Gamma rays	$III$. For $AM$ and $FM$ communication systems
$S$. Radio wave	$IV$. For treating the cancer cells

Electromagnetic waves with wavelengths ranging from $3 \times 10^{-3} \, m$ to $1 \, m$ are used in satellite communication. What is the corresponding frequency range? (Given $c = 3 \times 10^8 \, m/s$)

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