In which of the following conditions will the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) From the ideal gas equation,$PV = nRT$,the molar volume $V_m = \frac{V}{n} = \frac{RT}{P}$.Thus,$V_m \propto \frac{T}{P}$.For maximum molar volume

Vedclass · Accepted Answer

At $127\,^oC$ and $1\, atm$ pressure

Vedclass · Answer

(C) From the ideal gas equation,$PV = nRT$,the molar volume $V_m = \frac{V}{n} = \frac{RT}{P}$.Thus,$V_m \propto \frac{T}{P}$.For maximum molar volume,we need the highest temperature $(T)$ and the lowest pressure $(P)$.Comparing the conditions:$A$: $T = 273.15\, K, P = 1\, atm \implies \frac{T}{P} = 273.15$$B$: $T = 273.15\, K, P = 2\, atm \implies \frac{T}{P} = 136.57$$C$: $T = 127 + 273 = 400\, K, P = 1\, atm \implies \frac{T}{P} = 400$$D$: $T = 273 + 273 = 546\, K, P = 2\, atm \implies \frac{T}{P} = 273$Comparing the values,the ratio $\frac{T}{P}$ is maximum for option $C$.

In which of the following conditions will the molar volume of $CO_2$ be maximum?

Similar Questions

$A$ weather balloon filled with hydrogen at $1 \, atm$ and $27 \, ^oC$ has a volume equal to $12000 \, L$. On ascending,it reaches a place where the temperature is $-23 \, ^oC$ and the pressure is $0.5 \, atm$. The volume of the balloon is .............. $L$.

Explain the law relating pressure and temperature.

At constant temperature,in a given mass of an ideal gas,

If a gas expands from $20 \ cm^3$ to $50 \ cm^3$ at a constant temperature $(T)$ under a pressure of $1 \ atm$,what will be the final pressure?

$400 \ cm^{3}$ of oxygen at $27\,^{\circ}C$ were cooled to $-3\,^{\circ}C$ without change in pressure. The contraction in volume will be ............... $cm^{3}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module