The density of ammonia gas at 27^{circ}C and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Using the ideal gas equation $PV = nRT$,where $n = \frac{m}{M}$.Density $d = \frac{m}{V} = \frac{PM}{RT}$.For ammonia $(NH_3)$,molar mass $M = 14

Vedclass · Accepted Answer

$2.07 \, g \, dm^{-3}$

Vedclass · Answer

(B) Using the ideal gas equation $PV = nRT$,where $n = \frac{m}{M}$.Density $d = \frac{m}{V} = \frac{PM}{RT}$.For ammonia $(NH_3)$,molar mass $M = 14 + 3(1) = 17 \, g \, mol^{-1}$.Given $P = 3 \, atm$,$T = 27 + 273 = 300 \, K$,and $R = 0.0821 \, L \, atm \, K^{-1} \, mol^{-1}$.$d = \frac{3 	imes 17}{0.0821 	imes 300} = \frac{51}{24.63} \approx 2.07 \, g \, L^{-1}$.Since $1 \, L = 1 \, dm^3$,the density is $2.07 \, g \, dm^{-3}$.

The density of ammonia gas at $27^{\circ}C$ and $3 \, atm$ pressure is approximately:

Similar Questions

For an ideal gas,Boyle's law is best described by which of the following graphs?

The volume-temperature graphs of a given mass of an ideal gas at different constant pressures are shown below. What is the correct order of pressures?

The use of hot air balloons for sports and meteorological observations is based on which of the following laws?

Calculate the volume of gas at $1.25 \ atm$,if the volume occupied by the gas at $1 \ atm$ and at the same temperature is $25 \ mL$. (in $mL$)

An ideal gas weighing $9.0 \ g$ occupies a volume of $8.2 \ L$ at $300 \ K$ and $1 \ atm$ pressure. The molar mass of the gas is .....

Vedclass Test Series

Exam Paper Generator

Online Exam Module