What is the average kinetic energy per molecu | vedclass

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(B) The average kinetic energy per molecule is given by the formula: $E_k = \frac{3}{2} kT$ Here,$k$ is the Boltzmann constant,which is $1.38 	imes 1

Vedclass · Accepted Answer

$5.94 	imes 10^{-21} \, J$

Vedclass · Answer

(B) The average kinetic energy per molecule is given by the formula: $E_k = \frac{3}{2} kT$ Here,$k$ is the Boltzmann constant,which is $1.38 	imes 10^{-23} \, J \, K^{-1} \, 	ext{molecule}^{-1}$. The temperature $T$ in Kelvin is $25 + 273 = 298 \, K$. Substituting the values: $E_k = \frac{3}{2} 	imes (1.38 	imes 10^{-23} \, J \, K^{-1}) 	imes 298 \, K = 6.17 	imes 10^{-21} \, J$. Note: Using the standard value of $k = 1.38 	imes 10^{-23}$,the result is approximately $6.17 	imes 10^{-21} \, J$. Given the options provided in the question,the closest value is $5.94 	imes 10^{-21} \, J$ (which corresponds to using $k \approx 1.33 	imes 10^{-23}$).

What is the average kinetic energy per molecule of an ideal gas in $SI$ units at $25 \, ^\circ C$?

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