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(C) The $rms$ speed of a gas is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.At $T_1 = 27\,^oC = 300\,K$,the speed is $u_1 = \sqrt{\frac{3R \

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Double the previous value

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(C) The $rms$ speed of a gas is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.At $T_1 = 27\,^oC = 300\,K$,the speed is $u_1 = \sqrt{\frac{3R 	imes 300}{M}}$.At $T_2 = 927\,^oC = 1200\,K$,the speed is $u_2 = \sqrt{\frac{3R 	imes 1200}{M}}$.Calculating the ratio: $\frac{u_2}{u_1} = \sqrt{\frac{1200}{300}} = \sqrt{4} = 2$.Therefore,$u_2 = 2u_1$,which means the $rms$ speed becomes double the initial value.

If the temperature of a gas is increased from $27\,^oC$ to $927\,^oC$,what will be the change in its $rms$ speed?

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