When an ideal gas undergoes free expansion,then:

  • A
    Cooling occurs because molecules are at a temperature above the inversion temperature.
  • B
    No cooling occurs because no attractive forces exist between molecules.
  • C
    Cooling occurs because molecules lose energy by colliding with each other.
  • D
    No cooling occurs because it does work equal to the loss in kinetic energy $(KE)$.

Explore More

Similar Questions

In the equation $PV = nRT$,the number of moles per liter can be expressed as:

Pressure of $1 \ g$ ideal gas $X$ at $300 \ K$ is $2 \ atm$. When $2 \ g$ of another gas $Y$ is introduced in the same vessel at the same temperature,the total pressure becomes $3 \ atm$. The correct relationship between molar masses of $X$ and $Y$ is:

State the combined gas law and the ideal gas equation.

Difficult
View Solution

For an ideal gas,the $V$ vs $T$ plot at constant pressures $P_1$ and $P_2$ is shown in the figure. Which of the following is correct?

Calculate the new pressure of a gas enclosed in a cylinder when it is compressed from $5 \text{ L}$ to $2 \text{ L}$ at an initial pressure of $1 \text{ atm}$ and temperature of $300 \text{ K}$. The final temperature in this process is $500 \text{ K}$. (in $\text{ atm}$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo