(A) Let the oxidation number of carbon be $X$.In $CH_2Cl_2$,the oxidation number of hydrogen $(H)$ is $+1$ and chlorine $(Cl)$ is $-1$.Applying the ru

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(A) Let the oxidation number of carbon be $X$.In $CH_2Cl_2$,the oxidation number of hydrogen $(H)$ is $+1$ and chlorine $(Cl)$ is $-1$.Applying the rule for the sum of oxidation numbers in a neutral molecule:$X + 2(+1) + 2(-1) = 0$$X + 2 - 2 = 0$$X = 0$Therefore,the oxidation number of carbon in $CH_2Cl_2$ is $0$.