What is the oxidation number of sulfur in H_2 | vedclass

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(C) The structure of $H_2S_2O_8$ (peroxodisulfuric acid) is $HO-SO_2-O-O-SO_2-OH$.In this structure,there is a peroxide linkage $(-O-O-)$ where the ox

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$6$

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(C) The structure of $H_2S_2O_8$ (peroxodisulfuric acid) is $HO-SO_2-O-O-SO_2-OH$.In this structure,there is a peroxide linkage $(-O-O-)$ where the oxidation state of each oxygen atom is $-1$.The remaining six oxygen atoms are bonded to sulfur,each having an oxidation state of $-2$.Let the oxidation number of sulfur be $x$.Applying the sum of oxidation states equal to zero:$2(+1) + 2(x) + 2(-1) + 6(-2) = 0$$2 + 2x - 2 - 12 = 0$$2x - 12 = 0$$2x = 12$$x = +6$

What is the oxidation number of sulfur in $H_2S_2O_8$?

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