What are the oxidation numbers of sulfur in $S_8$,$S_2F_2$,and $H_2S$ respectively?

  • A
    $0, +1$ and $-2$
  • B
    $+2, +1$ and $-1$
  • C
    $0, +1$ and $+2$
  • D
    $-2, -1$ and $-2$

Explore More

Similar Questions

From the given list,the number of compounds with $+4$ oxidation state of Sulphur is $ . . . . . . $.
$SO_3, H_2SO_3, SOCl_2, SF_4, BaSO_4, H_2S_2O_7$

The oxidation number of oxygen in an $O_2$ molecule is:

Equivalent weight of $KMnO_4$ acting as an oxidant in acidic medium is equal to

Assertion: In some cases,oxygen exhibits a positive oxidation state. Consequently,it is an electronegative element.
Reason: Fluorine is more electronegative than oxygen.

Difficult
View Solution

Compounds having the highest oxidation state of the central atom act as acids,the lowest ones act as bases,and intermediate oxidation states act as amphoteric. Which one of the following is amphoteric?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo