In the following reaction,3CuO + 2NH_3 to N_2 | vedclass

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Question

(A) In the reaction $3CuO + 2\overset{-3}{N}H_3 	o \overset{0}{N_2} + 3H_2O + 3Cu$,the oxidation state of nitrogen changes from $-3$ in $NH_3$ to $0$

Vedclass · Accepted Answer

Per mole of $N_2$,$6$ electrons are lost.

Vedclass · Answer

(A) In the reaction $3CuO + 2\overset{-3}{N}H_3 	o \overset{0}{N_2} + 3H_2O + 3Cu$,the oxidation state of nitrogen changes from $-3$ in $NH_3$ to $0$ in $N_2$. For each nitrogen atom,$3$ electrons are lost $(0 - (-3) = 3)$. Since $N_2$ contains $2$ nitrogen atoms,the total number of electrons lost per mole of $N_2$ is $2 	imes 3 = 6$ electrons.

In the following reaction,$3CuO + 2NH_3 \to N_2 + 3H_2O + 3Cu$,what happens during the conversion of $NH_3$ to $N_2$?

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