What will 1 mol of MnO_4^{2-} produce upon d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The disproportionation reaction of manganate ion $(MnO_4^{2-})$ in neutral or acidic medium is given by: $3MnO_4^{2-} + 2H_2O 	o MnO_2 + 2MnO_4^-

Vedclass · Accepted Answer

$\frac{2}{3} \ mol \ MnO_4^-, \frac{1}{3} \ mol \ MnO_2$

Vedclass · Answer

(A) The disproportionation reaction of manganate ion $(MnO_4^{2-})$ in neutral or acidic medium is given by: $3MnO_4^{2-} + 2H_2O 	o MnO_2 + 2MnO_4^- + 4OH^-$. To find the products for $1 \ mol$ of $MnO_4^{2-}$,divide the entire equation by $3$: $MnO_4^{2-} + \frac{2}{3}H_2O 	o \frac{1}{3}MnO_2 + \frac{2}{3}MnO_4^- + \frac{4}{3}OH^-$. Thus,$1 \ mol$ of $MnO_4^{2-}$ produces $\frac{2}{3} \ mol$ of $MnO_4^-$ and $\frac{1}{3} \ mol$ of $MnO_2$.

What will $1 \ mol$ of $MnO_4^{2-}$ produce upon disproportionation in a neutral aqueous medium?

Similar Questions

Disproportionation of $1 \ mol$ of $MnO_4^{2-}$ in neutral aqueous solution results in which of the following?

$2CuI \to Cu + CuI_2$,the reaction is

What sorts of information can you draw from the following reaction?
$(CN)_{2}(g) + 2OH^{-}(aq) \rightarrow CN^{-}(aq) + CNO^{-}(aq) + H_{2}O(l)$

$Cu^{+}$ ion is not stable in aqueous solution,because it shows $-$

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$Ca(OH)_2 + Cl_2 \longrightarrow CaOCl_2 + H_2O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module