When $KMnO_4$ reacts with $Br^-$ in a basic medium to give bromate ion,the oxidation state of $Mn$ changes from $7$ to . . . . . .
- A$6$
- B$4$
- C$3$
- D$2$
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For the balanced equation $NO_3^- + 4H^+ + ne^- \to 2H_2O + NO$,the value of $n$ is ........
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View SolutionAssign $A$,$B$,$C$,$D$ from the given type of reaction.
$Ba(N_3)_2 \xrightarrow{\Delta} Ba + 3N_2 \uparrow$
$Ba(N_3)_2 \xrightarrow{\Delta} Ba + 3N_2 \uparrow$
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View SolutionIn alkaline condition $KMnO_4$ reacts as follows:
$2KMnO_4 + 2KOH \to 2K_2MnO_4 + H_2O + O$
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View Solution$H_2O_2$ reduces $MnO_4^-$ ion to:
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