(C) The electronic configuration of the element with atomic number $Z = 33$ is $[Ar]^{18} \, 3d^{10} \, 4s^2 \, 4p^3$. Since the last electron enters

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(C) The electronic configuration of the element with atomic number $Z = 33$ is $[Ar]^{18} \, 3d^{10} \, 4s^2 \, 4p^3$. Since the last electron enters the $p$-orbital,it is a $p$-block element. For $p$-block elements,the group number is calculated as $10 + (ns + np)$ electrons. Group number $= 10 + 2 + 3 = 15$.