BeF_2 is soluble in water,whereas fluorides o | vedclass

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(C) The solubility of ionic compounds in water is determined by the balance between lattice energy and hydration energy. For $BeF_2$,the hydration ene

Vedclass · Accepted Answer

The hydration energy of the $Be^{2+}$ ion is higher than its lattice energy.

Vedclass · Answer

(C) The solubility of ionic compounds in water is determined by the balance between lattice energy and hydration energy. For $BeF_2$,the hydration energy of the small $Be^{2+}$ ion is significantly higher than its lattice energy,which overcomes the lattice forces and makes it soluble in water. In contrast,for other alkaline earth metal fluorides,the lattice energy dominates,making them insoluble.

Column-$I$	Column-$II$
$(a)$ Calcium	$(p)$ Crimson red
$(b)$ Barium	$(q)$ Brick red
$(c)$ Strontium	$(r)$ Apple green
-	$(s)$ Yellow

$BeF_2$ is soluble in water,whereas fluorides of other alkaline earth metals are insoluble. The reason is ...

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Match column-$I$ with column-$II$ :
Column-$I$ Column-$II$
$(a)$ Calcium $(p)$ Crimson red
$(b)$ Barium $(q)$ Brick red
$(c)$ Strontium $(r)$ Apple green
- $(s)$ Yellow

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