If $ᴧ^{0} CH_{3}COONa = 91 \ S \ cm^{2} \ mol^{-1}$ and $ᴧ^{0} HCl = 462.2 \ S \ cm^{2} \ mol^{-1}$,then what value is required to calculate $ᴧ^{0} CH_{3}COOH$?

At $298 \ K$,the equivalent conductance of $0.1 \ M$ acetic acid is $5.20 \ S \ cm^{2} \ eq.^{-1}$. Calculate the degree of dissociation of acetic acid at this concentration in $\%$. Given: $\lambda^{\infty} (H^{+}) = 349.8 \ S \ cm^{2} \ mol^{-1}$ and $\lambda^{\infty} (CH_{3}COO^{-}) = 40.9 \ S \ cm^{2} \ mol^{-1}$.

If the specific conductivity of $0.1 \, N$ nitric acid is $6.2 \times 10^{-2} \, \Omega^{-1} \, cm^{-1}$,what will be the molar conductivity of the solution in $\Omega^{-1} \, cm^{2} \, mol^{-1}$?

Calculate $\Lambda _m^o$ for $CaCl_2$ and $MgSO_4$ from the data given in the table below:

Ion and $\lambda ^o / (S \ cm^2 \ mol^{-1})$	Ion and $\lambda ^o / (S \ cm^2 \ mol^{-1})$
$H^{+} : 349.6$	$OH^{-} : 199.1$
$Na^{+} : 50.1$	$Cl^{-} : 76.3$
$K^{+} : 73.5$	$Br^{-} : 78.1$
$Ca^{2+} : 119.0$	$CH_3COO^{-} : 40.9$
$Mg^{2+} : 106.0$	$SO_4^{2-} : 160.0$

Electrical conductance through metals is called metallic or electronic conductance and is due to the movement of electrons. The electronic conductance depends on

Which of the following options is true when an electrolyte solution is diluted?