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(C) The standard cell potential $E^o_{cell}$ is calculated using the formula: $E^o_{cell} = E^o_{cathode} - E^o_{anode}$.In the given cell $Zn_{(s)} |

Vedclass · Accepted Answer

$1.56$

Vedclass · Answer

(C) The standard cell potential $E^o_{cell}$ is calculated using the formula: $E^o_{cell} = E^o_{cathode} - E^o_{anode}$.In the given cell $Zn_{(s)} | Zn^{2+}_{(aq)} || Ag^{+}_{(aq)} | Ag_{(s)}$,the oxidation occurs at the $Zn$ electrode (anode) and reduction occurs at the $Ag$ electrode (cathode).Here,$E^o_{cathode} = E^o_{Ag^{+}/Ag} = +0.80 \ V$ and $E^o_{anode} = E^o_{Zn^{2+}/Zn} = -0.76 \ V$.Substituting the values: $E^o_{cell} = 0.80 \ V - (-0.76 \ V) = 0.80 \ V + 0.76 \ V = 1.56 \ V$.

Calculate the standard cell potential for the galvanic cell $Zn_{(s)} | Zn^{2+}_{(aq)} || Ag^{+}_{(aq)} | Ag_{(s)}$,given that $E^o_{Zn^{2+}/Zn} = -0.76 \ V$ and $E^o_{Ag^{+}/Ag} = +0.80 \ V$. (in $V$)

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