(B) In fused $CaH_2$,the dissociation occurs as: $CaH_2(l) \rightarrow Ca^{2+} + 2H^-$. At the cathode,the reduction of $Ca^{2+}$ ions occurs: $Ca^{2+

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(B) In fused $CaH_2$,the dissociation occurs as: $CaH_2(l) \rightarrow Ca^{2+} + 2H^-$. At the cathode,the reduction of $Ca^{2+}$ ions occurs: $Ca^{2+} + 2e^- \rightarrow Ca$. At the anode,the oxidation of hydride ions $(H^-)$ occurs: $2H^- \rightarrow H_2(g) + 2e^-$. Therefore,hydrogen gas is produced at the anode.

Class 11 Chemistry Hydrogen Hydrogen

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During the electrolysis of fused calcium hydride $(CaH_2)$,where is hydrogen produced?

A
Cathode
B
Anode
C
Hydrogen is not liberated anywhere.
D
The formed $H_2$ reacts with oxygen to form water.

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Hydrogen

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Hydrogen

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Very pure hydrogen $(99.9 \%)$ can be made by which of the following processes?

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Why does hydrogen occur in a diatomic form rather than in a monoatomic form under normal conditions?

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Hydrogen has three isotopes $(A)$,$(B)$ and $(C)$. If the number of neutron$(s)$ in $(A)$,$(B)$ and $(C)$ respectively,are $(x)$,$(y)$ and $(z)$,the sum of $(x)$,$(y)$ and $(z)$ is:

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During the electrolysis of fused calcium hydride $(CaH_2)$,where is hydrogen produced?

Similar Questions

Hydrogen iodide cannot be prepared by the action of concentrated $H_2SO_4$ on potassium iodide because:

The synonym for water gas when used in the production of methanol is:

Very pure hydrogen $(99.9 \%)$ can be made by which of the following processes?

Why does hydrogen occur in a diatomic form rather than in a monoatomic form under normal conditions?

Hydrogen has three isotopes $(A)$,$(B)$ and $(C)$. If the number of neutron$(s)$ in $(A)$,$(B)$ and $(C)$ respectively,are $(x)$,$(y)$ and $(z)$,the sum of $(x)$,$(y)$ and $(z)$ is:

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