The bond angle in PH_3 is closest to which of | vedclass

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(A) In the corresponding compound $NH_3$,the bond angle is $107^o$.However,in $PH_3$,the bond angle is approximately $90^o$.This is because,despite ha

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$90$

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(A) In the corresponding compound $NH_3$,the bond angle is $107^o$.However,in $PH_3$,the bond angle is approximately $90^o$.This is because,despite having a similar electronic structure,the electronegativity of the central atom $(P)$ is lower than that of $N$. As a result,the bonding electrons are further from the central atom,reducing the $bp-bp$ repulsion and causing the bond angle to decrease towards $90^o$.

List-$I$ (Compound)	List-$II$ (Structure)
$A$. $ClF_3$	$1$. Square planar
$B$. $PCl_5$	$2$. Tetrahedral
$C$. $IF_5$	$3$. Trigonal bipyramidal
$D$. $CCl_4$	$4$. Square pyramidal
$E$. $XeF_4$	$5$. $T$-shaped

The bond angle in $PH_3$ is closest to which of the following $^o$?

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