What are the hybridization states of carbon i | vedclass

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(C) In diamond,each carbon atom is bonded to four other carbon atoms in a tetrahedral geometry,resulting in $sp^3$ hybridization.In graphite,each carb

Vedclass · Accepted Answer

$sp^3, sp^2, sp$

Vedclass · Answer

(C) In diamond,each carbon atom is bonded to four other carbon atoms in a tetrahedral geometry,resulting in $sp^3$ hybridization.In graphite,each carbon atom is bonded to three other carbon atoms in a planar hexagonal arrangement,resulting in $sp^2$ hybridization.In acetylene $(C_2H_2)$,each carbon atom is bonded to one hydrogen atom and one other carbon atom via a triple bond,resulting in $sp$ hybridization.Therefore,the hybridization states are $sp^3, sp^2, sp$ respectively.

What are the hybridization states of carbon in diamond,graphite,and acetylene,respectively?

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