(A) In $IF_5$,the total number of valence electrons is $7 + (5 \times 7) = 42$. Using the formula for steric number $(X)$: $X = \frac{42}{8} = 5$ (quo

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(A) In $IF_5$,the total number of valence electrons is $7 + (5 \times 7) = 42$. Using the formula for steric number $(X)$: $X = \frac{42}{8} = 5$ (quotient) and $2$ (remainder). Then,$\frac{2}{2} = 1$ (quotient) and $0$ (remainder). $X = 5 + 1 = 6$. Since the steric number is $6$,the hybridization is $sp^3d^2$.