What is the correct order of bond angles (fro | vedclass

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(C) To determine the bond angles,we analyze the hybridization and the number of lone pairs on the central atom:CompoundHybridizationLone PairsBond Ang

Vedclass · Accepted Answer

$H_2S < NH_3 < SiH_4 < BF_3$

Vedclass · Answer

(C) To determine the bond angles,we analyze the hybridization and the number of lone pairs on the central atom:CompoundHybridizationLone PairsBond Angle$H_2S$$sp^3$$2$$\approx 92.2^o$$NH_3$$sp^3$$1$$\approx 107^o$$SiH_4$$sp^3$$0$$109.5^o$$BF_3$$sp^2$$0$$120^o$As the number of lone pairs increases,the bond angle decreases due to increased lone pair-bond pair repulsion.Therefore,the correct order is $H_2S < NH_3 < SiH_4 < BF_3$.

List-$I$	List-$II$
$A$. $XeF_4$	$1$. Pyramidal
$B$. $XeF_6$	$2$. $T$-shape
$C$. $XeO_3$	$3$. Distorted octahedral
$D$. $XeOF_2$	$4$. Square planar

What is the correct order of bond angles (from smallest to largest) in $H_2S, NH_3, BF_3,$ and $SiH_4$?

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