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(D) To determine the hybridization of the $C$ atom,we count the number of sigma bonds and lone pairs attached to it.$1$. In $HCOOH$ (formic acid),the

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$CH_3CHO$

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(D) To determine the hybridization of the $C$ atom,we count the number of sigma bonds and lone pairs attached to it.$1$. In $HCOOH$ (formic acid),the $C$ atom is bonded to $H$,$OH$,and double-bonded to $O$. It is $sp^2$ hybridized.$2$. In $(H_2N)_2CO$ (urea),the $C$ atom is bonded to two $NH_2$ groups and double-bonded to $O$. It is $sp^2$ hybridized.$3$. In $HCHO$ (formaldehyde),the $C$ atom is bonded to two $H$ atoms and double-bonded to $O$. It is $sp^2$ hybridized.$4$. In $CH_3CHO$ (acetaldehyde),the methyl carbon $(CH_3)$ is bonded to three $H$ atoms and one $C$ atom. Since it has four sigma bonds,it is $sp^3$ hybridized.

In which of the following compounds does the $C$ atom use $sp^3$ hybrid orbitals for bonding?

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