In the compound $CH \equiv C - CH = CH_2$,what is the hybridization of the carbons involved in the $C - C$ single bond?

  • A
    $sp^3 - sp^2$
  • B
    $sp^3 - sp^3$
  • C
    $sp - sp^2$
  • D
    $sp - sp^3$

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The number of $sp^{3}$ hybridised carbons in an acyclic neutral compound with molecular formula $C_{4}H_{5}N$ is.

In which of the following compounds is the underlined carbon atom $sp^3$ hybridized?

How many $(i)$ $sp^{2}$ hybridised carbon atoms and $(ii)$ $\pi$ bonds are present in the following compound?

In the reaction,the hybridisation states of carbon atoms $1, 2, 3, 4$ are:
$Br-CH=CH-Br \xrightarrow[Catalyst]{H_2} Br-CH_2-CH_2-Br$

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