(a) , CH_3CONH_2 + KOH + Br_2 rightarrow(b) , | vedclass

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(A) This is the Hofmann bromamide degradation reaction,which converts an amide to an amine with one less carbon atom.$(b)$ This is the decarboxylation

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Decrease in the number of carbon atoms

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(A) This is the Hofmann bromamide degradation reaction,which converts an amide to an amine with one less carbon atom.$(b)$ This is the decarboxylation reaction using soda lime,which removes $CO_2$ and results in an alkane with one less carbon atom.$(c)$ This is the Hunsdiecker reaction,which converts a silver salt of a carboxylic acid to an alkyl bromide with one less carbon atom.Therefore,all three reactions result in a decrease in the number of carbon atoms.

List-$I$	List-$II$
$A$. Amide	$I$. Carbylamine reaction
$B$. Nitrile	$II$. Hinsberg's reagent
$C$. $C_6H_5SO_2Cl$	$III$. Hofmann's bromamide reaction
$D$. $1^{\circ}$-Amine	$IV$. $LiAlH_4$

$(a) \, CH_3CONH_2 + KOH + Br_2 \rightarrow$
$(b) \, CH_3COOH + \text{Soda lime} \rightarrow$
$(c) \, CH_3COOAg + Br_2 \rightarrow$
What is the common feature in the above three reactions?

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Match the following:
List-$I$ List-$II$
$A$. Amide $I$. Carbylamine reaction
$B$. Nitrile $II$. Hinsberg's reagent
$C$. $C_6H_5SO_2Cl$ $III$. Hofmann's bromamide reaction
$D$. $1^{\circ}$-Amine $IV$. $LiAlH_4$

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$(a) \, CH_3CONH_2 + KOH + Br_2 \rightarrow$$(b) \, CH_3COOH + \text{Soda lime} \rightarrow$$(c) \, CH_3COOAg + Br_2 \rightarrow$What is the common feature in the above three reactions?