Before nitration of amino benzene,the -NH_2 g | vedclass

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Question

(B) Direct nitration of aniline $(C_6H_5NH_2)$ results in the formation of tarry oxidation products along with nitro derivatives because the $-NH_2$ g

Vedclass · Accepted Answer

Acetylation

Vedclass · Answer

(B) Direct nitration of aniline $(C_6H_5NH_2)$ results in the formation of tarry oxidation products along with nitro derivatives because the $-NH_2$ group is strongly activating and ortho/para-directing.To control the reaction and obtain the desired para-nitroaniline,the $-NH_2$ group is protected by acetylation using acetic anhydride or acetyl chloride to form acetanilide $(C_6H_5NHCOCH_3)$.This reduces the activating effect of the group and prevents oxidation,allowing for controlled nitration.

Before nitration of amino benzene,the $-NH_2$ group is first protected by which of the following processes?

Similar Questions

Identify the compound from the following having the highest basic strength.

Which of the following compounds is $NOT$ formed as an intermediate product in the Hofmann bromamide degradation reaction?

Identify the final product $Z$ in the following reaction sequence:

The order of basic strength of the following in aqueous solution is
$I$. $C_6H_5NH_2$
$II$. $(CH_3)_3N$
$III$. $NH_3$
$IV$. $CH_3NH_2$
$V$. $(CH_3)_2NH$

Consider the following compounds:
$I. CH_3-CH_2-NH_2$
$II. Ph-CH_2-NH_2$
$III. Ph-NH_2$
The correct order of their basic strength is:

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