What is obtained by the ammonolysis of alkyl | vedclass

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(D) The ammonolysis of alkyl halides involves the nucleophilic substitution reaction where the halogen atom is replaced by an amino group. $R-X + NH_3

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$A$ mixture of primary,secondary,tertiary amines and quaternary ammonium salt

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(D) The ammonolysis of alkyl halides involves the nucleophilic substitution reaction where the halogen atom is replaced by an amino group. $R-X + NH_3 \rightarrow R-NH_2 + HX$ Since the primary amine formed is also a nucleophile,it reacts further with the alkyl halide to form secondary and tertiary amines,and finally a quaternary ammonium salt. $R-NH_2 + R-X \rightarrow R_2NH + HX$ $R_2NH + R-X \rightarrow R_3N + HX$ $R_3N + R-X \rightarrow R_4N^+X^-$ Thus,the reaction produces a mixture of primary,secondary,tertiary amines and quaternary ammonium salt.

Column-$I$	Column-$II$
$A$. Benzenesulphonyl chloride	$1$. Zwitter ion
$B$. Sulphanilic acid	$2$. Hinsberg reagent
$C$. Alkyl diazonium salts	$3$. Dyes
$D$. Aryl diazonium salts	$4$. Conversion to alcohols

What is obtained by the ammonolysis of alkyl halides?

Similar Questions

For reaction-$I$,the reagents are $CH_3CONH_2, KOH, Br_2$. For reaction-$II$,the reagents are $CH_3NH_2, CHCl_3, KOH$. What are the intermediates for reaction-$I$ and reaction-$II$ respectively?

Which of the following is the strongest base in an aqueous solution?

What is obtained from the hydrolysis of isocyanide?

Match the compounds given in Column-$I$ with the items given in Column-$II$.

Column-$I$ Column-$II$

$A$. Benzenesulphonyl chloride $1$. Zwitter ion

$B$. Sulphanilic acid $2$. Hinsberg reagent

$C$. Alkyl diazonium salts $3$. Dyes

$D$. Aryl diazonium salts $4$. Conversion to alcohols

Identify $(a)$ and $(b)$ in the following reaction:
$CH_3CH_2NH_2 + CHCl_3 + 3KOH \rightarrow (a) + (b) + 3H_2O$

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