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(C) $N$-bromosuccinimide $(NBS)$ is a reagent used for free radical bromination at the benzylic position. In ethylbenzene $(C_6H_5CH_2CH_3)$,the benzy

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$1-$bromo$-1-$phenylethane

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(C) $N$-bromosuccinimide $(NBS)$ is a reagent used for free radical bromination at the benzylic position. In ethylbenzene $(C_6H_5CH_2CH_3)$,the benzylic carbon is the carbon atom directly attached to the benzene ring. The reaction proceeds via a free radical mechanism to replace a hydrogen atom on the benzylic carbon with a bromine atom. Thus,the reaction of ethylbenzene with $NBS$ yields $1-$bromo$-1-$phenylethane $(C_6H_5CH(Br)CH_3)$.

What is the product formed by the reaction between ethylbenzene and $N$-bromosuccinimide $(NBS)$?

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