Toluene is nitrated,and the resulting product | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. Nitration of toluene $(C_6H_5CH_3)$ gives a mixture of $o$-nitrotoluene and $p$-nitrotoluene.$2$. Reduction of these nitro compounds using $S

Vedclass · Accepted Answer

$O$ and $P$ bromotoluene

Vedclass · Answer

(D) $1$. Nitration of toluene $(C_6H_5CH_3)$ gives a mixture of $o$-nitrotoluene and $p$-nitrotoluene.$2$. Reduction of these nitro compounds using $Sn/HCl$ or $Fe/HCl$ yields $o$-toluidine and $p$-toluidine ($o$-methylaniline and $p$-methylaniline).$3$. Diazotization of these amines with $NaNO_2/HCl$ at $0-5 \ ^\circ C$ produces the corresponding diazonium salts ($o$-methylbenzenediazonium chloride and $p$-methylbenzenediazonium chloride).$4$. Heating these diazonium salts with cuprous bromide $(CuBr/HBr)$ (Sandmeyer reaction) replaces the diazonium group with a bromine atom,resulting in $o$-bromotoluene and $p$-bromotoluene.

Toluene is nitrated,and the resulting product is reduced. This is then diazotized and heated with cuprous bromide. What are the final products?

Similar Questions

$(i)$ Chlorobenzene and $(ii)$ benzene hexachloride are obtained from benzene by the reaction of chlorine,in the presence of

How will you obtain monobromobenzene from aniline?

The reaction in which copper$(I)$ salt is used to replace nitrogen in diazonium salt is called,

Identify the reagent used for the replacement of the $-N_2^+Cl^-$ group from benzene diazonium chloride by an iodine atom.

The chlorobenzene is generally obtained from a corresponding diazonium salt by reacting it with

Vedclass Test Series

Exam Paper Generator

Online Exam Module