What is formed when 1-propanamine is treated | vedclass

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(D) The reaction of $1-$propanamine $(CH_3CH_2CH_2NH_2)$ with $NaNO_2$ and $HCl$ produces a diazonium salt $(CH_3CH_2CH_2N_2^+Cl^-)$ as an intermediat

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All of the above

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(D) The reaction of $1-$propanamine $(CH_3CH_2CH_2NH_2)$ with $NaNO_2$ and $HCl$ produces a diazonium salt $(CH_3CH_2CH_2N_2^+Cl^-)$ as an intermediate. This aliphatic diazonium salt is highly unstable and decomposes to form a carbocation $(CH_3CH_2CH_2^+)$. The primary carbocation undergoes rearrangement to form a more stable secondary carbocation $(CH_3CH^+CH_3)$. These carbocations react with water,chloride ions,or undergo elimination to form a mixture of products including $1-$propanol,$2-$propanol,propene,$1-$chloropropane,and $2-$chloropropane. Therefore,all the mentioned products are formed.

What is formed when $1-$propanamine is treated with $NaNO_2$ and $HCl$?

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