(C) The atomic number of $Fe$ is $26$.The electronic configuration of neutral $Fe$ atom is $[Ar] 3d^6 4s^2$.When $Fe$ forms $Fe^{2+}$ ion,it loses two

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(C) The atomic number of $Fe$ is $26$.The electronic configuration of neutral $Fe$ atom is $[Ar] 3d^6 4s^2$.When $Fe$ forms $Fe^{2+}$ ion,it loses two electrons from the $4s$ orbital.Therefore,the electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.Thus,the number of $d$-electrons in $Fe^{2+}$ is $6$.