What is the general electronic configuration of actinoids?
- A$[Rn] \, 5f^{0-14} \, 6d^{0-1} \, 7s^2$
- B$[Rn] \, 5f^{1-14} \, 6d^{0-2} \, 7s^2$
- C$[Rn] \, 5f^{0-14} \, 6d^{1-2} \, 7s^2$
- D$[Rn] \, 5f^{0-14} \, 6d^{0-2} \, 7s^2$
Explore More
Similar Questions
Which among the following properties of lanthanoids is $NOT$ true?
$A$ member of the Lanthanoid series which is well known to exhibit $+4$ oxidation state is
Which of the following is not a consequence of the Lanthanoid contraction?
Medium
View SolutionThe lanthanide ion having four unpaired electrons is
(Given : Atomic number of $Ce = 58, Nd = 60, Tb = 65$ and $Ho = 67$)
(Given : Atomic number of $Ce = 58, Nd = 60, Tb = 65$ and $Ho = 67$)
MediumNEET 2026
View SolutionThe main reason for the actinoids exhibiting a larger number of oxidation states than the lanthanoids is:
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo