Identify the correct order of oxidizing power | vedclass

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(A) The oxidizing power of transition metal oxoanions depends on the reduction potential of the metal in its highest oxidation state. The standard red

Vedclass · Accepted Answer

$VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$

Vedclass · Answer

(A) The oxidizing power of transition metal oxoanions depends on the reduction potential of the metal in its highest oxidation state. The standard reduction potentials $(E^\circ)$ for the given species are: $VO_2^+ + 2H^+ + e^- \rightarrow VO^{2+} + H_2O$ $(E^\circ = 1.00 \ V)$ $Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O$ $(E^\circ = 1.33 \ V)$ $MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O$ $(E^\circ = 1.51 \ V)$ Since the oxidizing power increases with the increase in standard reduction potential,the order is $VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$.

Identify the correct order of oxidizing power.

Similar Questions

The number of ions from the following that have the ability to liberate hydrogen from a dilute acid is. . . . . . . .$Ti^{2+}, Cr^{2+}, V^{2+}$

Identify the incorrect statement.

For the four successive transition elements $(Cr, Mn, Fe, \text{ and } Co)$,the stability of $+2$ oxidation state will be in which of the following order?
(Atomic numbers: $Cr = 24, Mn = 25, Fe = 26, Co = 27$)

How would you account for the increasing oxidising power in the series $VO_2^+ < Cr_2O_7^{2-} < MnO_4^-$?

Iron exhibits $+2$ and $+3$ oxidation states. Which of the following statements is incorrect for iron?

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