When an acidic solution of K_2Cr_2O_7 is adde | vedclass

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Question

(B) The reaction between potassium dichromate $(K_2Cr_2O_7)$ and sodium sulfite $(Na_2SO_3)$ in an acidic medium $(H_2SO_4)$ is as follows:$K_2Cr_2O_7

Vedclass · Accepted Answer

$Cr_2(SO_4)_3$

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(B) The reaction between potassium dichromate $(K_2Cr_2O_7)$ and sodium sulfite $(Na_2SO_3)$ in an acidic medium $(H_2SO_4)$ is as follows:$K_2Cr_2O_7 + 3Na_2SO_3 + 4H_2SO_4 \rightarrow 3Na_2SO_4 + K_2SO_4 + 4H_2O + Cr_2(SO_4)_3$In this reaction,the orange dichromate ion $(Cr_2O_7^{2-})$ is reduced to the green chromium$(III)$ ion $(Cr^{3+})$,which forms chromium$(III)$ sulfate $(Cr_2(SO_4)_3)$.Thus,the green color is due to the formation of $Cr_2(SO_4)_3$.

When an acidic solution of $K_2Cr_2O_7$ is added to $Na_2SO_3$,it turns green. Which of the following compounds is formed in this reaction?

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