What is the electronic configuration of $Ce$ $(Z = 58)$?

  • A
    $[Xe] \, 4f^2 \, 5d^0 \, 6s^2$
  • B
    $[Xe] \, 4f^1 \, 5d^1 \, 6s^2$
  • C
    $[Xe] \, 4f^2 \, 5d^1 \, 6s^1$
  • D
    $[Xe] \, 4f^0 \, 5d^2 \, 6s^2$

Explore More

Similar Questions

Limiting compositions of $f$-block hydrides are

The atomic number of cerium $(Ce)$ is $58$. The correct electronic configuration of $Ce^{3+}$ ion is

Explain the lanthanoid contraction.

Larger number of oxidation states are exhibited by the actinoids than those by the lanthanoids,the main reason being

Fill in the blanks:
$1.$ The atomic radii of the elements of the third transition series are .......... to those of the corresponding elements of the second transition series.
$2.$ Samarium melts at .......... $K$.
$3.$ The color of lanthanoid ions is due to the presence of .......... electrons.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo