The common oxidation state of the elements of | vedclass

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Question

(B) The lanthanoids are a series of $14$ elements from Cerium ($Ce$,$Z=58$) to Lutetium ($Lu$,$Z=71$).All lanthanoids exhibit a common oxidation state

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$+3$

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(B) The lanthanoids are a series of $14$ elements from Cerium ($Ce$,$Z=58$) to Lutetium ($Lu$,$Z=71$).All lanthanoids exhibit a common oxidation state of $+3$ due to the loss of two $6s$ electrons and one $4f$ or $5d$ electron.While some elements show $+2$ or $+4$ oxidation states in specific compounds,$+3$ is the most stable and characteristic oxidation state for the entire series.

The common oxidation state of the elements of the lanthanoid series is .....

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