In the given compound,at which carbon number | vedclass

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(B) carbon atom is chiral if it is bonded to four different groups. In the given chain $CH_3-CH_2-CH_2-CH_2-CH_2-CH_2-CH_3$ (heptane),the carbons at p

Vedclass · Accepted Answer

$3$

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(B) carbon atom is chiral if it is bonded to four different groups. In the given chain $CH_3-CH_2-CH_2-CH_2-CH_2-CH_2-CH_3$ (heptane),the carbons at positions $1$ and $7$ are primary $(CH_3)$,and carbons $2, 3, 4, 5, 6$ are secondary $(CH_2)$. If we attach a new group (different from $H$ and the existing alkyl chain) to carbon $4$,it becomes bonded to four distinct groups: $H$,the new group,a propyl group $(-CH_2-CH_2-CH_3)$,and another propyl group $(-CH_2-CH_2-CH_3)$. However,since the two propyl groups are identical,it is not chiral. If we attach a new group to carbon $3$,the groups attached are $H$,the new group,an ethyl group $(-CH_2-CH_3)$,and a butyl group $(-CH_2-CH_2-CH_2-CH_3)$. Since all four groups are different,the carbon becomes chiral. Thus,attaching a group to carbon $3$ or $4$ creates a chiral center,but $4$ is the center of the chain. Let's re-evaluate: at $C_4$,we have two identical propyl groups. At $C_3$,we have an ethyl and a butyl group. Therefore,$C_3$ is the correct choice.

In the given compound,at which carbon number should a new group be attached to make the compound chiral? $1_{CH_3} - 2_{CH_2} - 3_{CH_2} - 4_{CH_2} - 5_{CH_2} - 6_{CH_2} - 7_{CH_3}$

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