The surface tension of a soap solution is $30 \times 10^{-3} \, N/m$. The work done to increase the surface area of a soap film from $5 \, cm \times 5 \, cm$ to $10 \, cm \times 10 \, cm$ is:

  • A
    $4.5 \times 10^{-4} \, J$
  • B
    $6.0 \times 10^{-4} \, J$
  • C
    $4.5 \times 10^{-5} \, J$
  • D
    $7.5 \times 10^{-4} \, J$

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