Arrange the gases H_2, CH_4, CO_2, and NH_3 i | vedclass

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Question

(D) The extent of adsorption of a gas on a solid adsorbent depends on the ease of liquefaction of the gas. Easily liquefiable gases have higher critic

Vedclass · Accepted Answer

$NH_3 > CO_2 > CH_4 > H_2$

Vedclass · Answer

(D) The extent of adsorption of a gas on a solid adsorbent depends on the ease of liquefaction of the gas. Easily liquefiable gases have higher critical temperatures $(T_c)$ and are adsorbed to a greater extent. The critical temperatures of the given gases are: $NH_3$ $(405.5 \ K)$ > $CO_2$ $(304.1 \ K)$ > $CH_4$ $(190.6 \ K)$ > $H_2$ $(33.2 \ K)$. Since the extent of adsorption follows the order of critical temperatures,the correct order of volume adsorbed is $NH_3 > CO_2 > CH_4 > H_2$.

Arrange the gases $H_2, CH_4, CO_2,$ and $NH_3$ in the order of their volume adsorbed on $1 \ g$ of charcoal at $288 \ K$.

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