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(B) The Freundlich adsorption isotherm is given by the equation: $\frac{x}{m} = k \cdot p^{1/n}$ (where $n > 1$).Taking the logarithm on both sides,we

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$\log(\frac{x}{m})$ vs $\log(p)$

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(B) The Freundlich adsorption isotherm is given by the equation: $\frac{x}{m} = k \cdot p^{1/n}$ (where $n > 1$).Taking the logarithm on both sides,we get: $\log(\frac{x}{m}) = \log(k) + \frac{1}{n} \log(p)$.This equation is in the form of a straight line $y = mx + c$,where $y = \log(\frac{x}{m})$,$x = \log(p)$,slope $m = \frac{1}{n}$,and intercept $c = \log(k)$.Therefore,the plot of $\log(\frac{x}{m})$ vs $\log(p)$ gives a straight line.

If $x$ amount of gas is adsorbed on $m$ amount of adsorbent at pressure $p$,the Freundlich adsorption isotherm plot gives a straight line for which of the following?

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