Ozonolysis of compound X followed by reductio | vedclass

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(A) Ozonolysis of an alkene followed by reduction with $Zn/H_2O$ breaks the $C=C$ double bond and adds an oxygen atom to each carbon atom.If the produ

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$2$-Butene

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(A) Ozonolysis of an alkene followed by reduction with $Zn/H_2O$ breaks the $C=C$ double bond and adds an oxygen atom to each carbon atom.If the product is two moles of the same aldehyde,the alkene must be symmetric.For $2$-Butene $(CH_3-CH=CH-CH_3)$,ozonolysis yields:$CH_3-CH=CH-CH_3 + O_3 \rightarrow 2CH_3CHO$ (Acetaldehyde).Thus,$X$ is $2$-Butene.

Ozonolysis of compound $X$ followed by reduction yields two moles of the same aldehyde. What is $X$?

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