What is the product formed when $n$-propyl bromide is reacted with ethanolic potassium hydroxide?

$(R)-2-$bromobutane upon treatment with $aq. \, NaOH$ gives

In the following pairs of halogen compounds,which compound undergoes faster $S_N1$ reaction?
$(i)$ $2$-chloro-$2$-methylpropane and $3$-chloropentane
(ii) $2$-chloroheptane and $1$-chlorohexane

The order of reactivity of the compounds $C_6H_5CH_2Br$,$C_6H_5CH(C_6H_5)Br$,$C_6H_5CH(CH_3)Br$ and $C_6H_5C(CH_3)(C_6H_5)Br$ in $S_N2$ reaction is

Tertiary alkyl halides are practically inert to $SN^2$ mechanism because of....

When $3-$methylbutan$-2-$ol is treated with $HBr$,the following reaction takes place:
$CH_3-CH(CH_3)-CH(OH)-CH_3 \xrightarrow{HBr} CH_3-C(Br)(CH_3)-CH_2-CH_3$
Give a mechanism for this reaction.
(Hint : The secondary carbocation formed in step $II$ rearranges to a more stable tertiary carbocation by a hydride ion shift from $3^{rd}$ carbon atom.)