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(A) This is an example of the $Hofmann$ elimination reaction.In the quaternary ammonium hydroxide $[CH_3CH_2CH_2-N^+(CH_3)_2-CH_2CH_3] OH^-$,there are

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$CH_2=CH_2$

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(A) This is an example of the $Hofmann$ elimination reaction.In the quaternary ammonium hydroxide $[CH_3CH_2CH_2-N^+(CH_3)_2-CH_2CH_3] OH^-$,there are two types of $\beta$-hydrogens available for elimination.Elimination occurs to form the least substituted alkene according to $Hofmann's$ rule.The $\beta$-hydrogens on the ethyl group are more accessible and acidic compared to those on the propyl group.Therefore,the major product formed is $CH_2=CH_2$ (ethene).

Consider the following reaction. What is the major product formed?
$[CH_3CH_2CH_2-N^+(CH_3)_2-CH_2CH_3] OH^- \xrightarrow{\text{Heat}}$

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Consider the following reaction. What is the major product formed?$[CH_3CH_2CH_2-N^+(CH_3)_2-CH_2CH_3] OH^- \xrightarrow{\text{Heat}}$