CH_2 = CH_2 xrightarrow[KOH/H_2O]{KMnO_4} X = | vedclass

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Question

(A) The reaction of ethene $(CH_2 = CH_2)$ with cold,dilute alkaline potassium permanganate $(KMnO_4)$ solution is known as Baeyer's reagent test.This

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Ethylene glycol

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(A) The reaction of ethene $(CH_2 = CH_2)$ with cold,dilute alkaline potassium permanganate $(KMnO_4)$ solution is known as Baeyer's reagent test.This reaction results in the hydroxylation of the double bond to form a vicinal diol.$CH_2 = CH_2 + H_2O + [O] \xrightarrow{KMnO_4/OH^-} HO-CH_2-CH_2-OH$ (Ethylene glycol).Thus,the product $X$ is ethylene glycol.

$CH_2 = CH_2 \xrightarrow[KOH/H_2O]{KMnO_4} X = ......$

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