The dehydrobromination of 2-bromobutane resul | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dehydrobromination of $2$-bromobutane $(CH_3-CHBr-CH_2-CH_3)$ follows $Saytzeff's$ rule.According to this rule,the more substituted alkene is

Vedclass · Accepted Answer

Predominantly $2$-butene

Vedclass · Answer

(A) The dehydrobromination of $2$-bromobutane $(CH_3-CHBr-CH_2-CH_3)$ follows $Saytzeff's$ rule.According to this rule,the more substituted alkene is the major product.$2$-bromobutane can undergo elimination to form either $1$-butene $(CH_2=CH-CH_2-CH_3)$ or $2$-butene $(CH_3-CH=CH-CH_3)$.$2$-butene is a disubstituted alkene,while $1$-butene is a monosubstituted alkene.Since $2$-butene is more stable due to hyperconjugation and inductive effects,it is formed as the major product.

The dehydrobromination of $2$-bromobutane results in the formation of which of the following?

Similar Questions

If all the nucleophilic substitution reactions at saturated carbon atoms in the above sequence of reactions follow $S_N2$ mechanism, then $\underline{E}$ and $\underline{E}$ will be respectively,

Arrange the following organic halides in the correct order of reactivity towards $S_{N}2$ displacement:
$(P) \ (CH_3)_2C(Br)CH_2CH_3$
$(Q) \ BrCH_2(CH_2)_3CH_3$
$(R) \ CH_3CH(Br)(CH_2)_2CH_3$

Determine the number of chiral products (including stereoisomers) formed upon $E_2$ elimination of the given substrate with $alc. KOH$.

The one giving the maximum number of isomeric alkenes on dehydrohalogenation reaction is (excluding rearrangement):

What is the major product formed when $2$-bromopentane is heated with ethanolic potassium ethoxide $(C_2H_5OK)$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module