A hydrocarbon C_6H_{10} absorbs only one mole | vedclass

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(A) $1$. The molecular formula $C_6H_{10}$ corresponds to the general formula $C_nH_{2n-2}$,indicating the presence of either one triple bond or two d

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Cyclohexene

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(A) $1$. The molecular formula $C_6H_{10}$ corresponds to the general formula $C_nH_{2n-2}$,indicating the presence of either one triple bond or two double bonds or a ring with one double bond.$2$. Since it absorbs only one molecule of $H_2$,it must contain exactly one double bond (or one triple bond that is reduced to a double bond,but the ozonolysis product suggests a cyclic structure).$3$. Ozonolysis of the hydrocarbon yields $CHO(CH_2)_4CHO$,which is hexanedial. This indicates that the original molecule was a cyclic compound with a double bond in the ring.$4$. $A$ cyclic $C_6$ hydrocarbon with one double bond is cyclohexene. Ozonolysis of cyclohexene breaks the double bond to form the open-chain dialdehyde $CHO(CH_2)_4CHO$.

$A$ hydrocarbon $C_6H_{10}$ absorbs only one molecule of $H_2$ upon catalytic hydrogenation. Upon ozonolysis,it yields $CHO(CH_2)_4CHO$. What is the hydrocarbon?

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