If the products of ozonolysis are acetone and | vedclass

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(C) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds.Acetone is $CH_3-CO-CH_3$ and formaldehyde is $H

Vedclass · Accepted Answer

$CH_3-C(CH_3)=CH_2$

Vedclass · Answer

(C) Ozonolysis of an alkene involves the cleavage of the $C=C$ double bond to form carbonyl compounds.Acetone is $CH_3-CO-CH_3$ and formaldehyde is $H-CHO$.By removing the oxygen atoms from these products and joining the carbonyl carbons with a double bond,we get the structure of the alkene:$(CH_3)_2C=O + O=CH_2 ightarrow (CH_3)_2C=CH_2$.The starting substance is $2-	ext{methylpropene}$,which is $CH_3-C(CH_3)=CH_2$.

If the products of ozonolysis are acetone and formaldehyde,what is the starting substance?

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