Which of the following compounds contains car | vedclass

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(D) $1$. In $C_4H_{10}$ (butane),all carbon atoms are $sp^3$ hybridized.$2$. In $CH_3-CH=CH-CH_3$ (but$-2-$ene),the terminal carbons are $sp^3$ hybrid

Vedclass · Accepted Answer

Both $CH_3-CH=CH-CH_3$ and $CH_2=CH-C\equiv CH$

Vedclass · Answer

(D) $1$. In $C_4H_{10}$ (butane),all carbon atoms are $sp^3$ hybridized.$2$. In $CH_3-CH=CH-CH_3$ (but$-2-$ene),the terminal carbons are $sp^3$ hybridized,while the carbons involved in the double bond are $sp^2$ hybridized.$3$. In $CH_2=CH-C\equiv CH$ (but$-1-$en$-3-$yne),the terminal $CH_2$ carbon is $sp^2$,the middle $CH$ carbon is $sp^2$,and the carbons in the triple bond are $sp$ hybridized.$4$. Since both $CH_3-CH=CH-CH_3$ and $CH_2=CH-C\equiv CH$ contain carbon atoms with different types of hybridization,the correct answer is $D$.

Which of the following compounds contains carbon atoms with more than one type of hybridization?

Similar Questions

The hybridisations of carbon-$2$ in $P$ and $Q$ are respectively:

Which one amongst the following possesses an $sp$ hybridized carbon in its structure?

What is the type of hybridisation of each carbon atom in the following compounds?
$(a)$ $CH_{3}Cl$
$(b)$ $(CH_{3})_{2}CO$
$(c)$ $CH_{3}CN$
$(d)$ $HCONH_{2}$
$(e)$ $CH_{3}CH=CHCN$

Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:
$H_2C=C=CH-CHO$
(Order: $sp^3 - sp^2 - sp$)

What hybrid orbitals are present in the following compound $H_3C - CH = CH - CH_2 - CH_3$?

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